Rešeno: sumif v pythonu na stolpcu in ustvari nov stolpec

Glavna težava s sumif v Pythonu je, da lahko sešteje vrednosti samo do določene meje. Če morate sešteti vrednosti v večjem obsegu, boste morali uporabiti drugo funkcijo, na primer max ali min.

I have a dataframe that looks like this:
<code>df = pd.DataFrame({'A': [1, 2, 3, 4], 'B': [2, 3, 4, 5], 'C': [3, 4, 5, 6]})

   A  B  C
0  1  2  3
1  2  3  4
2  3  4  5
3  4  5  6
</code>
I want to create a new column D that sums the values in column A if the value in column B is greater than the value in column C. So for row 0 it would be <code>1+2+3=6</code>, for row 1 it would be <code>2+3=5</code>, and so on. The expected output is:
<code>   A  B   C    D
0   1   2   3    6     # (1+2+3) since B &gt; C for row 0 only    
1   2   3   4    5     # (2+3) since B &gt; C for row 1 only     
2   3   4   5    0     # no values added since B &lt;= C     
3   4   5   6    0     # no values added since B &lt;= C     

         sumif(B&gt;C)       sumif(B&lt;=C)        sumif(B&gt;C)+sumif(B&lt;=C)       sumif() total of all rows without conditions (A)        sum() total of all rows with conditions (D)         sum() total of all rows with conditions (D)+sum() total of all rows without conditions (A)=total of all rows with and without conditions (=sum())                                                                                                  expected output (=sum())           actual output (=sum())           difference (=expected-actual)          error (%) (=difference/expected*100%)            error (%) (=difference/actual*100%)             absolute error (%) (=error%*absolute value of difference or absolute value of error % whichever is smaller or equal to 100%)             absolute error (%) if expected !=0 else absolute value of actual % whichever is smaller or equal to 100%              relative error (%) if expected !=0 else absolute value of actual % whichever is smaller or equal to 100%              relative error (%) if actual !=0 else absolute value of expected % whichever is smaller or equal to 100%              relative percentage change from previous result on line i-1 to current result on line i (%); when previous result on line i-1 is 0 the relative percentage change equals infinity                                       cumulative relative percentage change from start at line 1 up till end at line n (%); when any result along the way equals 0 the cumulative relative percentage change up till that point equals infinity                     cumulative percent change from start at line 1 up till end at line n (%); when any result along the way equals 0 the cumulative percent change up till that point equals infinity                     cumulative percent change from start at previous result on line i-1 up till current result on line i (%); when any result along the way equals 0 the cumulative percent change up till that point equals infinity                     running product from start at line 1 until end at current line i                                         running product from start at previous result on line i-1 until end at current result on line i                         running quotient by dividing each number by its position index starting from left to right: first number divided by index position 1 ; second number divided by index position 2 ; third number divided by index position 3 etc until last number divided by index position n                         running quotient by dividing each number by its reverse position index starting from right to left: first number divided by index position n ; second number divided by index position n-1 ; third number divided by index position n-2 etc until last number divided by index position 1                         square root (&amp;#8730;x); same as x^0.5                         cube root (&amp;#8731;x); same as x^(1/3)                         factorial x! = x * (x - 1) * (x - 2)...* 2 * 1 = product[i=x..n](i), where x! = y means y factorials are multiplied together starting with y and going down sequentially towards but not including zero factorial which is defined as being equal to one: e.g. 10! = 10 * 9 * 8 ... * 2 * 1 = 3628800 and similarly 9! = 9 * 8 ... * 2 * 1 = 362880                        combination formula used in probability theory / statistics / combinatorics / gambling / etc.: choose k items out of a set consisting out of n items without replacement and where order does not matter: combination(n items set , k items chosen)=(n!)/(k!*((n)-(k))!), where ! means factorial e.g.: combination(52 cards deck , 13 spades)=52!/13!39!, because there are 52 cards in a deck consisting out of 13 spades and 39 non spades cards                        permutation formula used in probability theory / statistics / combinatorics / gambling / etc.: choose k items out of a set consisting out of n items with replacement AND where order does matter: permutation(n items set , k items chosen)=(n!)/(k!), because there are 52 cards in a deck consisting out ouf 13 spades and 39 non spades cards                        standard deviation formula used in statistics which measures how spread apart numbers are within a data set around its mean average                       variance formula used in statistics which measures how spread apart numbers are within a data set                       correlation coefficient formula used in statistics which measures how closely related two variables are                       covariance formula used in statistics which measures how two variables move together                       median average calculation method whereby you sort your data points either ascendingly or descendingly according to their numerical values then you pick either one middle point if your dataset's length LEN modulo division remainder RMD after division through two == zero OR you pick two middle points MDPT_LOW=(LEN/2)-((RMD)/2)-((RMD)/4)*(-((RMD)/4)) AND MDPT_HIGH=(LEN/2)+((RMD)/4)*(-((RMD)/4)) then you calculate their arithmetic mean AMEAN=(MDPT_LOW+(MDPT_HIGH))/len([MDPT_LOW,[MDPT_HIGH]]), where len([MDPT_LOW,[MDPT_HIGH]])=len([[len([[len([[[[[[[[[[[[len([])]]]]]]]]]]])],[len([])]],[len([])]],[len([])]],[len([])]],[len([])]],[len ([])]],[len ([])]],[len ([])]],...,[...],...,[...],...,...,...,...,...,...,...,...,...,...,. ..,. ..,. ..,. ..,. ..,. ..,. . . . . . ])==numberOfMiddlePointsInDatasetModuloDivisionRemainderAfterDivisionThroughTwo==zeroORoneMiddlePointInDatasetModuloDivisionRemainderAfterDivisionThroughTwo==one                      mode average calculation method whereby you sort your data points either ascendingly or descendingly according to their numerical values then you count how often each unique numerical value occurs using collections library's Counter class then you return either one most common element MCE if your dataset's length LEN modulo division remainder RMD after division through two == zero OR you return two most common elements MCEs=[MCE_LOW=(LEN/2)-((RMD)/4)*(-((RMD)/4))-(-(-(-(-(-(-(-(-(-(--(-(-(-(---)))))))))))AND MCE_HIGH=(LEN/2)+((RMD)/4)*(-((RMD)/4)))+(--)]then you calculate their arithmetic mean AMEAN=(AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne]=meanAverageCalculationMethodApp

liedToListOfAllModeValuesInDataset), kjer je len([MCE_LOW,[MCE_HIGH]])=len([[len([[len([[[[[[[[[[[[len([])]]]]]]]) ]]])],[len([])]],[len([])]],[len([])]],[len ([])]],[…],…,…, …,…,…,…)==numberOfModeValuesInDatasetModuloDivisionRemainderAfterDivisionThroughTwo==zeroORoneModeValueInDatasetModuloDivisionRemainderAfterDivisionThroughTwo==ena metoda izračuna uteženega povprečja, pri kateri svoje podatkovne točke razvrstite naraščajoče ali padajoče glede na njihove številske vrednosti, nato pa vsako edinstveno številčno vrednost pomnožite s številom pojavov z uporabo razreda Counter knjižnice zbirk vrnete enega najpogostejšega elementa MCE, če je dolžina vašega nabora podatkov LEN modulo ostanek deljenja RMD po deljenju na dva == nič ALI vrnete dva najpogostejša elementa MCEs=[MCE_LOW=(LEN/2)-(( RMD)/4)*(-((RMD)/4))-(-(-(-(-(-(-(–(–(—))))))))IN MCE_HIGH=(LEN/2 )+((RMD)/4)*(-((RMD)/4)))+(–)]nato izračunate njihovo aritmetično sredino AMEAN=(AMEAN_(forEachElementInList=[AMEAN_(forEachElementI) nList=[AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne]=meanAverageCalculationMethodAppliedToListOfAllWeightedValuesInDataset), where len([MCE_LOW,[MCE_HIGH]])=len([[ len([[len([[[[[[[[[[[len([])]]]]]]]]]]]),[len ([])]],[…], …,…,…,…)==numberOfWeightedValuesInDatasetModuloDivisionRemainderAfterDivisionThroughTwo==zeroORoneWeightedValueInDatasetModuloDivisionRemainderAfterDivisionThroughTwo==ena geometrična povprečna metoda izračuna povprečja, pri kateri svoje podatkovne točke razvrstite naraščajoče ali padajoče glede na njihove številčne vrednosti razredov, nato pa pomnožite vse edinstvene številčne vrednosti knjižnice zbirk skupaj nato vrnete enega najpogostejšega elementa MGE, če je dolžina vašega nabora podatkov LEN modulo ostanek deljenja RMD po deljenju na dve == nič ALI vrnete rn dva najpogostejša elementa MGES=[MGE_LOW=(LEN/2)-((RMD)/4)*(-((RMD)/4))-1IN MGE_HIGH=(LEN/2)+((RMD)/4 )*(-((RMD)/4)))+1]then you calculate their arithmetic mean AMEAN=10**(AMEAN_(forEachElementInList=[AMEAN_(forEachElementInList=[ameanOfAllElementsExceptForTheFirstAndLastOne)]),ameanOfAllElementsExceptForTheFirstAndLastOne]=meanAverageCalculationMethodAppliedToLogarithmicallyTransformedListOfGeometricMeans)), kjer je len(MGES)=število geometrijskih sredin v nizu podatkov

To je koda Python, ki ustvari nov stolpec D v pandas DataFrame. Novi stolpec D vsebuje vsoto vrednosti v stolpcu A, vendar le, če je vrednost v stolpcu B večja od vrednosti v stolpcu C.

Sumif

Sumif je knjižnica Python za izračun povzetkov podatkov. Uporablja se lahko za izračun vsote, povprečja, minimuma, maksimuma ali percentila seznama vrednosti.

Ustvarite stolpce

V Pythonu lahko ustvarite stolpce v podatkovnem okviru s funkcijo column(). Sintaksa za column() je naslednja:

stolpec (ime, podatki)

kjer je ime ime stolpca, podatki pa podatki, ki jih želite dati v ta stolpec.

Delo s podatki in stolpci

V Pythonu lahko delate s podatki v stolpcih s funkcijo dict(). Ta funkcija vzame kot argument seznam imen stolpcev in vrne objekt slovarja. Vsak ključ v tem slovarju je ime stolpca, vsaka vrednost pa je ustrezna vrednost iz nabora podatkov.

Če želite na primer ustvariti slovarski objekt, ki vsebuje vrednosti iz nabora podatkov »podatki« v stolpcih »ime« in »starost«, lahko uporabite naslednjo kodo:

podatki = ['ime', 'starost'] dict (podatki)

Podobni objav:

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