Solved: rename duplicates in list python

Renaming duplicates in a list can be a difficult problem to solve because it requires you to identify the duplicates and then decide how to rename them. This can be especially challenging if the list contains many elements or if the elements are complex objects. Additionally, renaming duplicates may require you to modify other parts of your code that rely on the original names of the elements in order for them to continue functioning properly.

def rename_duplicates(lst): 
    seen = set() 
    new_lst = [] 

    for item in lst: 
        if item not in seen: 
            new_item = item + '_1'   # append a suffix to make it unique  

            while new_item in seen:   # increment the suffix until it's unique  
                suffix = int(new_item.split('_')[-1]) + 1   # get the last number and add one to it  
                new_item = '{}_{}'.format('_'.join(new_item.split('_')[:-1]), suffix)

            seen.add(new_item)     # add the newly created item to the set of seen items  
            new_lst.append(new_item)     # append the newly created item to the list

    return new


# This code defines a function called rename_duplicates that takes in a list as an argument.
def rename_duplicates(lst):

# It then creates an empty set called seen and an empty list called new_lst.
seen = set()
new_lst = []

# It then iterates through the items in the list and checks if they are already in the set of seen items.
for item in lst:
if item not in seen: # If it is not, it adds it to the set of seen items and appends it to the new list.
new_lst.append(item) # If it is, it creates a unique version of that item by adding a suffix (e.g., ‘_1’) to its name and checks if this newly created item is already in the set of seen items.

else: # If so, it increments the suffix until it finds an unused version of that item name and adds this newly created item to both the set of seen items and to the new list before returning this new list at the end of its execution.

new_item = item + ‘_1’

while new_item in seen: # increment suffix until unique

suffix = int(new_item.split(‘_’)[-1]) + 1 # get last number & add one to it

new_item = ‘{}_{}’.format(‘_’.join(new_item.split(‘_’)[:-1]), suffix)


Lists in Python

Lists in Python are one of the most commonly used data structures. They are used to store a collection of items, which can be of any type, including other lists. Lists are mutable, meaning they can be changed after they have been created. They also support operations such as indexing, slicing, and concatenation.

To create a list in Python, you use square brackets and separate each item with a comma:

my_list = [1, 2, 3]

You can access individual elements in the list using their index:
my_list[0] # returns 1
my_list[1] # returns 2
my_list[2] # returns 3

You can also use negative indices to access elements from the end of the list:

my_list[-1] # returns 3 (the last element)

You can add items to a list using the append() method:

my_list.append(4) # adds 4 to the end of the list

You can remove items from a list using either the remove() or pop() methods:

my_list.remove(3) # removes 3 from the list

my_list.pop(2) # removes and returns 2 (the third element) from the list

Rename duplicates in list in Python

Rename duplicates in list in Python is a common task when dealing with lists. It involves replacing duplicate elements in a list with unique values. This can be done using the set() function, which removes all duplicate elements from a list and returns a new list with only unique elements. The set() function can also be used to rename duplicates by providing it with a mapping of old values to new values. For example, if you have a list of numbers and want to replace all the duplicates with their respective squares, you could use the following code:

# Create an empty dictionary
mapping = {}

# Iterate over the original list
for item in my_list:
# Check if item already exists in dictionary
if item not in mapping:
# If not, add it to dictionary and assign its square as value
mapping[item] = item * item

# Create an empty result list
result_list = []

# Iterate over original list again and replace each element by its square from dictionary for i in my_list: result_list.append(mapping[i])

# Print result print(result_list)

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